4. Вычислите: $$(\sqrt{128} - \sqrt{32}) \cdot 8\sqrt{2}$$

$$\sqrt{128} = \sqrt{64 \cdot 2} = 8\sqrt{2}$$ $$\sqrt{32} = \sqrt{16 \cdot 2} = 4\sqrt{2}$$ $$(\sqrt{128} - \sqrt{32}) \cdot 8\sqrt{2} = (8\sqrt{2} - 4\sqrt{2}) \cdot 8\sqrt{2} = 4\sqrt{2} \cdot 8\sqrt{2} = 32 \cdot 2 = 64$$ Ответ: 64