\[ \frac{52}{4+\sqrt{3}} \cdot \frac{4-\sqrt{3}}{4-\sqrt{3}} = \frac{52(4-\sqrt{3})}{4^2 - (\sqrt{3})^2} = \frac{52(4-\sqrt{3})}{16 - 3} = \frac{52(4-\sqrt{3})}{13} \]
\[ \frac{52}{13}(4-\sqrt{3}) = 4(4-\sqrt{3}) = 16 - 4\sqrt{3} \]
\[ (16 - 4\sqrt{3}) + 4\sqrt{3} = 16 \]
Ответ: 16