Задание 36
Важно знать:
\( (a \cdot b)^n = a^n \cdot b^n \)
\( (a^m)^n = a^{m \cdot n} \)
Выполните возведение в степень
- \( (6^2)^3 = 6^{2 \cdot 3} = 6^6 \)
- \( (a^5)^{10} = a^{5 \cdot 10} = a^{50} \)
- \( (c^4)^{12} = c^{4 \cdot 12} = c^{48} \)
- \( (k^5)^5 = k^{5 \cdot 5} = k^{25} \)
- \( (p^4)^5 = p^{4 \cdot 5} = p^{20} \)
- \( (y^{10})^2 = y^{10 \cdot 2} = y^{20} \)
- \( (m^3)^6 = m^{3 \cdot 6} = m^{18} \)
- \( (x^{15})^3 = x^{15 \cdot 3} = x^{45} \)
- \( (q^7)^6 = q^{7 \cdot 6} = q^{42} \)
- \( (n^{25})^4 = n^{25 \cdot 4} = n^{100} \)
- \( (t^5)^{20} = t^{5 \cdot 20} = t^{100} \)
- \( (c^4)^{16} = c^{4 \cdot 16} = c^{64} \)
- \( (k^{13})^3 = k^{13 \cdot 3} = k^{39} \)
- \( (a^{11})^5 = a^{11 \cdot 5} = a^{55} \)
- \( (k^3 n)^2 = (k^3)^2 n^2 = k^6 n^2 \)
Представьте степень в виде произведения степеней
- \( (ab)^5 = a^5 \cdot b^5 \)
- \( (xy)^3 = x^3 \cdot y^3 \)
- \( (an)^2 = a^2 \cdot n^2 \)
- \( (2a)^5 = 2^5 \cdot a^5 \)
- \( (5c)^2 = 5^2 \cdot c^2 \)
- \( (3ab)^4 = 3^4 \cdot a^4 \cdot b^4 \)
- \( (10xy)^5 = 10^5 \cdot x^5 \cdot y^5 \)
- \( (4mn)^3 = 4^3 \cdot m^3 \cdot n^3 \)
- \( (abc)^7 = a^7 \cdot b^7 \cdot c^7 \)
- \( (xyz)^3 = x^3 \cdot y^3 \cdot z^3 \)
- \( (2x^2)^3 = 2^3 \cdot (x^2)^3 = 8x^6 \)
- \( (4a^3)^2 = 4^2 \cdot (a^3)^2 = 16a^6 \)
- \( (9m^2)^2 = 9^2 \cdot (m^2)^2 = 81m^4 \)
- \( (-5n^3)^2 = (-5)^2 \cdot (n^3)^2 = 25n^6 \)
- \( (-2a^6)^3 = (-2)^3 \cdot (a^6)^3 = -8a^{18} \)
Найдите значение выражения
- \( 2^5 \cdot 5^5 = (2 \cdot 5)^5 = 10^5 = 100000 \)
- \( 14^6 \cdot (\frac{1}{7})^6 = (14 \cdot \frac{1}{7})^6 = 2^6 = 64 \)
- \( 0.25^9 \cdot 4^9 = (0.25 \cdot 4)^9 = 1^9 = 1 \)
- \( (2^2)^3 : 2^3 = 2^{2 \cdot 3} : 2^3 = 2^6 : 2^3 = 2^{6-3} = 2^3 = 8 \)
- \( \frac{(2^{10})^2 : 2^7}{2^7} = \frac{2^{10 \cdot 2} : 2^7}{2^7} = \frac{2^{20} : 2^7}{2^7} = \frac{2^{20-7}}{2^7} = \frac{2^{13}}{2^7} = 2^{13-7} = 2^6 = 64 \)
- \( \frac{5^{13} \cdot 5^7}{(5^4)^5} = \frac{5^{13+7}}{5^{4 \cdot 5}} = \frac{5^{20}}{5^{20}} = 5^{20-20} = 5^0 = 1 \)
- \( \frac{3^{10} \cdot (3^3)^3}{3^{16}} = \frac{3^{10} \cdot 3^{3 \cdot 3}}{3^{16}} = \frac{3^{10} \cdot 3^9}{3^{16}} = \frac{3^{10+9}}{3^{16}} = \frac{3^{19}}{3^{16}} = 3^{19-16} = 3^3 = 27 \)
- \( \frac{(2^4)^3 \cdot (2^5)^2}{(2^3)^6} = \frac{2^{4 \cdot 3} \cdot 2^{5 \cdot 2}}{2^{3 \cdot 6}} = \frac{2^{12} \cdot 2^{10}}{2^{18}} = \frac{2^{12+10}}{2^{18}} = \frac{2^{22}}{2^{18}} = 2^{22-18} = 2^4 = 16 \)
- \( 2^3 \cdot 4^3 = 2^3 \cdot (2^2)^3 = 2^3 \cdot 2^{2 \cdot 3} = 2^3 \cdot 2^6 = 2^{3+6} = 2^9 = 512 \)
- \( 16^2 \cdot 4^3 : 8^4 = (2^4)^2 \cdot (2^2)^3 : (2^3)^4 = 2^{4 \cdot 2} \cdot 2^{2 \cdot 3} : 2^{3 \cdot 4} = 2^8 \cdot 2^6 : 2^{12} = 2^{8+6} : 2^{12} = 2^{14} : 2^{12} = 2^{14-12} = 2^2 = 4 \)
- \( 625 \cdot 5^7 : 125^3 = 5^4 \cdot 5^7 : (5^3)^3 = 5^{4+7} : 5^{3 \cdot 3} = 5^{11} : 5^9 = 5^{11-9} = 5^2 = 25 \)
- \( 100^3 \cdot 10^{12} : 1000^4 = (10^2)^3 \cdot 10^{12} : (10^3)^4 = 10^{2 \cdot 3} \cdot 10^{12} : 10^{3 \cdot 4} = 10^6 \cdot 10^{12} : 10^{12} = 10^{6+12} : 10^{12} = 10^{18} : 10^{12} = 10^{18-12} = 10^6 \)
- \( \frac{(2^2)^9 \cdot 8}{2^{20}} = \frac{2^{2 \cdot 9} \cdot 2^3}{2^{20}} = \frac{2^{18} \cdot 2^3}{2^{20}} = \frac{2^{18+3}}{2^{20}} = \frac{2^{21}}{2^{20}} = 2^{21-20} = 2^1 = 2 \)
- \( \frac{27 \cdot (3^4)^6}{3^{20} \cdot 3^5} = \frac{3^3 \cdot 3^{4 \cdot 6}}{3^{20} \cdot 3^5} = \frac{3^3 \cdot 3^{24}}{3^{20+5}} = \frac{3^{3+24}}{3^{25}} = \frac{3^{27}}{3^{25}} = 3^{27-25} = 3^2 = 9 \)
- \( \frac{5^{15} \cdot 5^{12}}{125 \cdot (5^8)^3} = \frac{5^{15+12}}{5^3 \cdot 5^{8 \cdot 3}} = \frac{5^{27}}{5^3 \cdot 5^{24}} = \frac{5^{27}}{5^{3+24}} = \frac{5^{27}}{5^{27}} = 5^{27-27} = 5^0 = 1 \)