a) \(\frac{3}{16} + \frac{4}{16} = \frac{3+4}{16} = \frac{7}{16}\)
б) \(12 \frac{6}{13} - 8 \frac{4}{13} = (12 - 8) + (\frac{6}{13} - \frac{4}{13}) = 4 + \frac{2}{13} = 4 \frac{2}{13}\)
в) \(5 \frac{17}{21} - 3 \frac{8}{21} + 4 \frac{7}{21} = (5 - 3 + 4) + (\frac{17}{21} - \frac{8}{21} + \frac{7}{21}) = 6 + \frac{16}{21} = 6 \frac{16}{21}\)
г) \(6 \frac{5}{13} + 2 \frac{8}{13} = (6 + 2) + (\frac{5}{13} + \frac{8}{13}) = 8 + \frac{13}{13} = 8 + 1 = 9\)
д) \(5 \frac{4}{7} + 3 \frac{6}{7} = (5 + 3) + (\frac{4}{7} + \frac{6}{7}) = 8 + \frac{10}{7} = 8 + 1 \frac{3}{7} = 9 \frac{3}{7}\)
e) \(1 - \frac{15}{19} = \frac{19}{19} - \frac{15}{19} = \frac{4}{19}\)
ж) \(8 - 3 \frac{4}{9} = 7 \frac{9}{9} - 3 \frac{4}{9} = (7 - 3) + (\frac{9}{9} - \frac{4}{9}) = 4 + \frac{5}{9} = 4 \frac{5}{9}\)
з) \(7 \frac{3}{8} - 2 \frac{5}{8} = 6 \frac{11}{8} - 2 \frac{5}{8} = (6 - 2) + (\frac{11}{8} - \frac{5}{8}) = 4 + \frac{6}{8} = 4 \frac{3}{4}\)
и) \(14 \frac{15}{32} - 9 \frac{19}{32} = 13 \frac{47}{32} - 9 \frac{19}{32} = (13 - 9) + (\frac{47}{32} - \frac{19}{32}) = 4 + \frac{28}{32} = 4 \frac{7}{8}\)
Ответ: См. решение выше