Решение:
2 \(\frac{45}{47}\) = \(\frac{2*47+45}{47}\) = \(\frac{94+45}{47}\) = \(\frac{139}{47}\)
3 \(\frac{39}{47}\) = \(\frac{3*47+39}{47}\) = \(\frac{141+39}{47}\) = \(\frac{180}{47}\)
7 \(\frac{41}{47}\) = \(\frac{7*47+41}{47}\) = \(\frac{329+41}{47}\) = \(\frac{370}{47}\)
22 \(\frac{2}{47}\) = \(\frac{22*47+2}{47}\) = \(\frac{1034+2}{47}\) = \(\frac{1036}{47}\)
32 - \(\frac{139}{47}\) - \(\frac{180}{47}\) + x - \(\frac{370}{47}\) = \(\frac{1036}{47}\)
-\(\frac{139+180+370}{47}\) = -\(\frac{689}{47}\)
x = \(\frac{1036}{47}\) + \(\frac{689}{47}\) - 32
x = \(\frac{1036+689}{47}\) - \(\frac{32*47}{47}\)
x = \(\frac{1725}{47}\) - \(\frac{1504}{47}\)
x = \(\frac{1725-1504}{47}\) = \(\frac{221}{47}\)
\(\frac{221}{47}\) = 4 \(\frac{33}{47}\)
Ответ: 4 \(\frac{33}{47}\)