\( \frac{15-10+3}{17} = \frac{8}{17} \)
\( (2+6) + (\frac{5}{7}+\frac{3}{7}) = 8 + \frac{8}{7} = 8 + 1\frac{1}{7} = 9\frac{1}{7} \)
\( 7\frac{6}{6} - 2\frac{5}{6} = (7-2) + (\frac{6}{6}-\frac{5}{6}) = 5 + \frac{1}{6} = 5\frac{1}{6} \)
\( 3\frac{15}{11} - 2\frac{10}{11} = (3-2) + (\frac{15}{11}-\frac{10}{11}) = 1 + \frac{5}{11} = 1\frac{5}{11} \)