Вопрос:

в) \((\sqrt{32} + 2\sqrt{18})\cdot \sqrt{2}\) г) \((2\sqrt{50} - 5\sqrt{2})\cdot \sqrt{2}\)

Ответ:

Решение:

  1. \((\sqrt{32} + 2\sqrt{18})\cdot \sqrt{2} = (\sqrt{16 \cdot 2} + 2\sqrt{9 \cdot 2})\cdot \sqrt{2} = (4\sqrt{2} + 2\cdot 3\sqrt{2})\cdot \sqrt{2} = (4\sqrt{2} + 6\sqrt{2})\cdot \sqrt{2} = 10\sqrt{2} \cdot \sqrt{2} = 10 \cdot 2 = 20\)
  2. \((2\sqrt{50} - 5\sqrt{2})\cdot \sqrt{2} = (2\sqrt{25 \cdot 2} - 5\sqrt{2})\cdot \sqrt{2} = (2\cdot 5\sqrt{2} - 5\sqrt{2})\cdot \sqrt{2} = (10\sqrt{2} - 5\sqrt{2})\cdot \sqrt{2} = 5\sqrt{2} \cdot \sqrt{2} = 5 \cdot 2 = 10\)

Ответ: в) 20; г) 10.

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