The image shows a chemical reaction sequence: C3H8 -> C3H7Cl -> C4H10 -> X, with t,AlCl3 indicated above the last arrow.

Chemical Reaction Analysis

The image displays a sequence of chemical transformations:

1. Starting Material: Propane (C3H8).
2. Step 1: Conversion of propane to propyl chloride (C3H7Cl). This is likely a free radical halogenation where a chlorine atom replaces a hydrogen atom on the propane molecule.
3. Step 2: Conversion of propyl chloride to butane (C4H10). This step suggests a coupling reaction, such as the Wurtz reaction, where two propyl groups are joined together. Alternatively, if the C3H7Cl is formed as a mixture of isomers (1-chloropropane and 2-chloropropane), the reaction with a metal like sodium or magnesium in the presence of an alkyl halide could lead to a mixture of alkanes, including butane. Given the simple progression, a dimerization is implied.
4. Step 3: Conversion of butane (C4H10) to product X in the presence of t,AlCl3. Aluminum chloride (AlCl3) is a Lewis acid commonly used as a catalyst in Friedel-Crafts alkylation and isomerization reactions. Since butane is an alkane, it can undergo isomerization in the presence of AlCl3 to form isobutane (2-methylpropane). The 't' likely refers to temperature or a specific condition.

Product X: Given the catalyst AlCl3 and an alkane (butane), the most probable reaction is isomerization.

Therefore, X is likely isobutane (2-methylpropane) with the formula C4H10.

Answer: X = C4H10 (isobutane)