4) $$tg(x-\frac{\pi}{3}) = \sqrt{3}$$

Решим уравнение $$tg(x-\frac{\pi}{3}) = \sqrt{3}$$. $$x-\frac{\pi}{3} = arctg(\sqrt{3}) + \pi n, n \in Z$$ $$x-\frac{\pi}{3} = \frac{\pi}{3} + \pi n, n \in Z$$ $$x = \frac{2\pi}{3} + \pi n, n \in Z$$ Ответ: $$x = \frac{2\pi}{3} + \pi n, n \in Z$$