Solve the system of equations: {2x+3y=-1, 3x+5y=-2}

1. Multiply the first equation by 3 and the second by 2: 3(2x+3y) = 3(-1) => 6x+9y=-3; 2(3x+5y) = 2(-2) => 6x+10y=-4.

2. Subtract the first modified equation from the second: (6x+10y) - (6x+9y) = -4 - (-3), which simplifies to y = -1.

3. Substitute y=-1 into the first original equation: 2x + 3(-1) = -1. Solve for x: 2x - 3 = -1 => 2x = 2 => x = 1.

Answer: x=1, y=-1