Solve the following arithmetic problems, filling in the blanks.

Решение:

Заполним пропуски в задачах:

1. \( \frac{7}{12} + \frac{1}{6} = \frac{7}{12} + \frac{2}{12} = \frac{9}{12} = \frac{3}{4} \)
2. \( \frac{3}{4} : 2 = \frac{3}{4} \times \frac{1}{2} = \frac{3}{8} \)
3. \( \frac{3}{8} \times \frac{4}{5} = \frac{12}{40} = \frac{3}{10} \)
4. \( \frac{3}{10} : \frac{3}{10} = 1 \)
5. \( 1 - \frac{1}{3} = \frac{2}{3} \)
6. \( \frac{1}{3} : 1 \frac{1}{3} = \frac{1}{3} : \frac{4}{3} = \frac{1}{3} \times \frac{3}{4} = \frac{1}{4} \)
7. \( \frac{2}{15} \cdot \frac{5}{6} = \frac{10}{90} = \frac{1}{9} \)
8. \( \frac{1}{9} + \frac{3}{8} = \frac{8}{72} + \frac{27}{72} = \frac{35}{72} \)
9. \( \frac{35}{72} : \frac{2}{3} = \frac{35}{72} \times \frac{3}{2} = \frac{105}{144} = \frac{35}{48} \)

Ответ: Заполненные ячейки: 1. 3/4, 2. 3/8, 3. 3/10, 4. 1, 5. 2/3, 6. 1/4, 7. 1/9, 8. 35/72, 9. 35/48