a) $$ \frac{a^2-11}{a-\sqrt{11}} = \frac{(a-\sqrt{11})(a+\sqrt{11})}{a-\sqrt{11}} = a+\sqrt{11} $$
б) $$ \frac{3-\sqrt{x}}{x-9} = \frac{3-\sqrt{x}}{(\sqrt{x}-3)(\sqrt{x}+3)} = -\frac{1}{\sqrt{x}+3} $$
в) $$ \frac{3\sqrt{a}-5\sqrt{b}}{9a-25b} = \frac{3\sqrt{a}-5\sqrt{b}}{(3\sqrt{a}-5\sqrt{b})(3\sqrt{a}+5\sqrt{b})} = \frac{1}{3\sqrt{a}+5\sqrt{b}} $$
г) $$ \frac{14+\sqrt{7}}{\sqrt{7}} = \frac{\sqrt{7}(2\sqrt{7}+1)}{\sqrt{7}} = 2\sqrt{7}+1 $$
Ответ: a) a+√11; б) -1/(√x+3); в) 1/(3√a+5√b); г) 2√7+1