Ответ:
\[2x^{2} + 7x - 4 = 0\]
\[D = 49 + 32 = 81\]
\[x_{1} = \frac{- 7 + 9}{4} = \frac{2}{4} = \frac{1}{2} = 0,5;\]
\[x_{2} = \frac{- 7 - 9}{4} = - 4.\]
\[Ответ:x = - 4;\ \ x = 0,5.\]
\[2x^{2} + 7x - 4 = 0\]
\[D = 49 + 32 = 81\]
\[x_{1} = \frac{- 7 + 9}{4} = \frac{2}{4} = \frac{1}{2} = 0,5;\]
\[x_{2} = \frac{- 7 - 9}{4} = - 4.\]
\[Ответ:x = - 4;\ \ x = 0,5.\]