Решите уравнение: 6x+(3x-2)=14.

\[6x + (3x - 2) = 14\]

\[6x + 3x - 2 = 14\]

\[9x = 14 + 2\]

\[9x = 16\]

\[x = \frac{16}{9}\]

\[x = 1\frac{7}{9}.\]