Решите уравнение: 3x^2+11x-20=0.

Question

\[3x^{2} + 11x - 20 = 0\]

\[D = 121 + 240 = 361 = 19^{2}\]

\[x_{1} = \frac{- 11 + 19}{6} = \frac{8}{6} = \frac{4}{3} = 1\frac{1}{3};\]

\[x_{2} = \frac{- 11 - 19}{6} = - \frac{30}{6} = - 5.\]

Accepted Answer

\[3x^{2} + 11x - 20 = 0\]

\[D = 121 + 240 = 361 = 19^{2}\]

\[x_{1} = \frac{- 11 + 19}{6} = \frac{8}{6} = \frac{4}{3} = 1\frac{1}{3};\]

\[x_{2} = \frac{- 11 - 19}{6} = - \frac{30}{6} = - 5.\]

Ответ: