Решите уравнение: 1) 10 5/8 − x = 7 3/5; 2) (x − 2 7/8) + 3 5/6 = 4 2/3.

1. \(10\frac{5}{8}-x=7\frac{3}{5}\).

   Выразим неизвестное: \(x=10\frac{5}{8}-7\frac{3}{5}\).

   НОК(8, 5) = 40: \(10\frac{25}{40}-7\frac{24}{40}=3\frac{1}{40}\).

2. \((x-2\frac{7}{8})+3\frac{5}{6}=4\frac{2}{3}\).

   \(x-2\frac{7}{8}=4\frac{2}{3}-3\frac{5}{6}=\frac{14}{3}-\frac{23}{6}=\frac{28}{6}-\frac{23}{6}=\frac{5}{6}\).

   \(x=2\frac{7}{8}+\frac{5}{6}\). НОК(8, 6) = 24: \(2\frac{21}{24}+\frac{20}{24}=3\frac{17}{24}\).

Ответ: 1) \(x=3\frac{1}{40}\); 2) \(x=3\frac{17}{24}\).