5.520 Решите уравнение: а) \frac{2}{3}x = 1; в) \frac{3}{10}a = 1; д) \frac{7}{25}x = \frac{7}{25}; б) \frac{51}{62}y = 1; г) \frac{104}{183}b = 1; e) \frac{13}{6}y = \frac{13}{6}.

Ответ: а) \(x = 1\frac{1}{2}\); б) \(y = 1\frac{11}{51}\); в) \(a = 3\frac{1}{3}\); г) \(b = 1\frac{79}{104}\); д) \(x = 1\); e) \(y = 1\)

Решаем:

а) \(\frac{2}{3}x = 1\)

\(x = 1 : \frac{2}{3}\)

\(x = 1 \cdot \frac{3}{2}\)

\(x = \frac{3}{2}\)

\(x = 1\frac{1}{2}\)

б) \(\frac{51}{62}y = 1\)

\(y = 1 : \frac{51}{62}\)

\(y = 1 \cdot \frac{62}{51}\)

\(y = \frac{62}{51}\)

\(y = 1\frac{11}{51}\)

в) \(\frac{3}{10}a = 1\)

\(a = 1 : \frac{3}{10}\)

\(a = 1 \cdot \frac{10}{3}\)

\(a = \frac{10}{3}\)

\(a = 3\frac{1}{3}\)

г) \(\frac{104}{183}b = 1\)

\(b = 1 : \frac{104}{183}\)

\(b = 1 \cdot \frac{183}{104}\)

\(b = \frac{183}{104}\)

\(b = 1\frac{79}{104}\)

д) \(\frac{7}{25}x = \frac{7}{25}\)

\(x = \frac{7}{25} : \frac{7}{25}\)

\(x = \frac{7}{25} \cdot \frac{25}{7}\)

\(x = 1\)

е) \(\frac{13}{6}y = \frac{13}{6}\)

\(y = \frac{13}{6} : \frac{13}{6}\)

\(y = \frac{13}{6} \cdot \frac{6}{13}\)

\(y = 1\)

Ответ: а) \(x = 1\frac{1}{2}\); б) \(y = 1\frac{11}{51}\); в) \(a = 3\frac{1}{3}\); г) \(b = 1\frac{79}{104}\); д) \(x = 1\); e) \(y = 1\)