Решите уравнение:

\[2006x^{2} + 2005x - 1 = 0\]

\[D = 2005^{2} - 4 \cdot 2006 \cdot ( - 1) =\]

\[= 4\ 020\ 025 + 8024 =\]

\[= 4\ 028\ 049\]

\[\sqrt{D} = \sqrt{4028049} = 2007.\]

\[x_{1} = \frac{- 2005 + 2007}{2 \cdot 2006} = \frac{2}{4012} =\]

\[= \frac{1}{2006}\]

\[x_{2} = \frac{- 2005 - 2007}{2 \cdot 2006} = \frac{- 4012}{4012} =\]

\[= - 1\]

\[Ответ:\ \frac{1}{2006};\ - 1.\]