Вопрос:
Решите пропорции.
Ответ:
Решаем пропорции:
Д:
0,4 : y = 2 : 9
y = (0,4 * 9) / 2
y = 3,6 / 2
\(y = 1,8\)
Е:
\(\frac{x}{6} = \frac{5,1}{17}\)
- \(x = \frac{6 \cdot 5,1}{17}\)
- \(x = \frac{30,6}{17}\)
- \(x = 1,8\)
Ж:
6 : 7 = x : 0,7
\(x = \frac{6 \cdot 0,7}{7}\)
- \(x = \frac{4,2}{7}\)
- \(x = 0,6\)
3:
\(\frac{5,4}{18} = \frac{b}{7}\)
\(b = \frac{5,4 \cdot 7}{18}\)
\(b = \frac{37,8}{18}\)
\(b = 2,1\)
Д:
- 13 : 15 = 2,6 : x
- \[x = \frac{15 \cdot 2,6}{13}\]
- \(x = \frac{39}{13}\)
- \(x = 3\)
Е:
- \[\frac{13}{x} = \frac{7}{1,4}\]
- \(x = \frac{13 \cdot 1,4}{7}\)
- \(x = \frac{18,2}{7}\)
- \(x = 2,6\)
Ж:
- \[\frac{11}{5,5} = \frac{16}{c}\]
- \(c = \frac{16 \cdot 5,5}{11}\)
- \(c = \frac{88}{11}\)
- \(c = 8\)
3:
- a : 0,5 = 7 : 5
- \(a = \frac{0,5 \cdot 7}{5}\)
- \(a = \frac{3,5}{5}\)
- \(a = 0,7\)
Д:
- 13 : 20 = 2,6 : a
- \(a = \frac{20 \cdot 2,6}{13}\)
- \(a = \frac{52}{13}\)
- \(a = 4\)
Е:
- 14 : 9 = y : 1,8
- \(y = \frac{14 \cdot 1,8}{9}\)
- \(y = \frac{25,2}{9}\)
- \(y = 2,8\)
Ж:
- \[\frac{3,8}{19} = \frac{y}{3}\]
- \(y = \frac{3,8 \cdot 3}{19}\)
- \(y = \frac{11,4}{19}\)
- \(y = 0,6\)
3:
- \[\frac{a}{13} = \frac{3,2}{14}\]
- \(a = \frac{13 \cdot 3,2}{14}\)
- \(a = \frac{41,6}{14}\)
- \(a = 2,97\) (округлённо)