Решение:
- \( x + 3 \geq 17 \)
\( x \geq 17 - 3 \)
\( x \geq 14 \) - \( x - 8 < 10 \)
\( x < 10 + 8 \)
\( x < 18 \) - \( 4 \leq y + 7 \)
\( 4 - 7 \leq y \)
\( -3 \leq y \) - \( -5 \geq 7 - y \)
\( -5 - 7 \geq -y \)
\( -12 \geq -y \)
\( 12 \leq y \) - \( 3x \geq x - 8 \)
\( 3x - x \geq -8 \)
\( 2x \geq -8 \)
\( x \geq -4 \) - \( 4x \leq 3x + 5 \)
\( 4x - 3x \leq 5 \)
\( x \leq 5 \) - \( 13x \geq -39 \)
\( x \geq \frac{-39}{13} \)
\( x \geq -3 \) - \( -5 < \frac{x}{2} \)
\( -5 \cdot 2 < x \)
\( -10 < x \) - \( -8x \leq 48 \)
\( x \geq \frac{48}{-8} \)
\( x \geq -6 \) - \( 7.2x \geq -36 \)
\( x \geq \frac{-36}{7.2} \)
\( x \geq -5 \) - \( \frac{x}{3} \leq 4 \)
\( x \leq 4 \cdot 3 \)
\( x \leq 12 \) - \( -2.5x \geq 5 \)
\( x \leq \frac{5}{-2.5} \)
\( x \leq -2 \) - \( 3x - 12 \geq 0 \)
\( 3x \geq 12 \)
\( x \geq 4 \) - \( 10 - 5x \geq 0 \)
\( 10 \geq 5x \)
\( 2 \geq x \) - \( 2x - 7 \leq 0 \)
\( 2x \leq 7 \)
\( x \leq 3.5 \) - \( 24 - 6x \leq 0 \)
\( 24 \leq 6x \)
\( 4 \leq x \) - \( 15 - 3x \geq 0 \)
\( 15 \geq 3x \)
\( 5 \geq x \) - \( 4x + 10 \leq 0 \)
\( 4x \leq -10 \)
\( x \leq -2.5 \) - \( 0.9x + 81 \geq 0 \)
\( 0.9x \geq -81 \)
\( x \geq \frac{-81}{0.9} \)
\( x \geq -90 \) - \( -\frac{1}{2}x - \frac{1}{8} \leq 0 \)
\( -\frac{1}{2}x \leq \frac{1}{8} \)
\( x \geq \frac{1}{8} \cdot (-2) \)
\( x \geq -\frac{1}{4} \) - \( 16 - \frac{2}{5}x > 0 \)
\( 16 > \frac{2}{5}x \)
\( 16 \cdot \frac{5}{2} > x \)
\( 40 > x \)
Ответ: 1. \( x \geq 14 \); 2. \( x < 18 \); 3. \( y \geq -3 \); 4. \( y \geq 12 \); 5. \( x \geq -4 \); 6. \( x \leq 5 \); 7. \( x \geq -3 \); 8. \( x > -10 \); 9. \( x \geq -6 \); 10. \( x \geq -5 \); 11. \( x \leq 12 \); 12. \( x \leq -2 \); 13. \( x \geq 4 \); 14. \( x \leq 2 \); 15. \( x \leq 3.5 \); 16. \( x \geq 4 \); 17. \( x \leq 5 \); 18. \( x \leq -2.5 \); 19. \( x \geq -90 \); 20. \( x \geq -0.25 \); 21. \( x < 40 \).