Вопрос:

Представьте степень в виде произведения степеней: 16) (ab)⁵ = 17) (xy)³ = 18) (an)² = 19) (2a)⁵ = 20) (5c)² = 21) (3ab)⁴ = 22) (10xy)⁵ = 23) (4mn)³ = 24) (abc)⁷ = 25) (xyz)³ = 26) (2x²)³ = 27) (4a³)² = 28) (9m²)² = 29) (-5n³)² = 30) (-2a⁶)³ =

Ответ:

Решение:

  1. \( (ab)^5 = a^5 b^5 \)
  2. \( (xy)^3 = x^3 y^3 \)
  3. \( (an)^2 = a^2 n^2 \)
  4. \( (2a)^5 = 2^5 a^5 \)
  5. \( (5c)^2 = 5^2 c^2 \)
  6. \( (3ab)^4 = 3^4 a^4 b^4 \)
  7. \( (10xy)^5 = 10^5 x^5 y^5 \)
  8. \( (4mn)^3 = 4^3 m^3 n^3 \)
  9. \( (abc)^7 = a^7 b^7 c^7 \)
  10. \( (xyz)^3 = x^3 y^3 z^3 \)
  11. \( (2x^2)^3 = 2^3 (x^2)^3 = 8 x^{2 \cdot 3} = 8x^6 \)
  12. \( (4a^3)^2 = 4^2 (a^3)^2 = 16 a^{3 \cdot 2} = 16a^6 \)
  13. \( (9m^2)^2 = 9^2 (m^2)^2 = 81 m^{2 \cdot 2} = 81m^4 \)
  14. \( (-5n^3)^2 = (-5)^2 (n^3)^2 = 25 n^{3 \cdot 2} = 25n^6 \)
  15. \( (-2a^6)^3 = (-2)^3 (a^6)^3 = -8 a^{6 \cdot 3} = -8a^{18} \)

Ответ: a⁵b⁵; x³y³; a²n²; 2⁵a⁵; 5²c²; 3⁴a⁴b⁴; 10⁵x⁵y⁵; 4³m³n³; a⁷b⁷c⁷; x³y³z³; 8x⁶; 16a⁶; 81m⁴; 25n⁶; -8a¹⁸.

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