Ответ: Решения представлены ниже
21) \[\frac{3}{75} + \frac{71}{450} = \frac{3 \cdot 6}{75 \cdot 6} + \frac{71}{450} = \frac{18}{450} + \frac{71}{450} = \frac{18 + 71}{450} = \frac{89}{450}\]
22) \[\frac{4}{7} - \frac{16}{28} = \frac{4 \cdot 4}{7 \cdot 4} - \frac{16}{28} = \frac{16}{28} - \frac{16}{28} = 0\]
23) \[\frac{4}{6} - \frac{5}{18} = \frac{4 \cdot 3}{6 \cdot 3} - \frac{5}{18} = \frac{12}{18} - \frac{5}{18} = \frac{12 - 5}{18} = \frac{7}{18}\]
24) \[\frac{2}{7} - \frac{3}{14} = \frac{2 \cdot 2}{7 \cdot 2} - \frac{3}{14} = \frac{4}{14} - \frac{3}{14} = \frac{4 - 3}{14} = \frac{1}{14}\]
25) \[\frac{7}{15} - \frac{1}{5} = \frac{7}{15} - \frac{1 \cdot 3}{5 \cdot 3} = \frac{7}{15} - \frac{3}{15} = \frac{7 - 3}{15} = \frac{4}{15}\]
26) \[\frac{10}{15} - \frac{2}{3} = \frac{10}{15} - \frac{2 \cdot 5}{3 \cdot 5} = \frac{10}{15} - \frac{10}{15} = 0\]
27) \[\frac{22}{9} - \frac{7}{3} = \frac{22}{9} - \frac{7 \cdot 3}{3 \cdot 3} = \frac{22}{9} - \frac{21}{9} = \frac{22 - 21}{9} = \frac{1}{9}\]
28) \[\frac{4}{7} - \frac{4}{21} = \frac{4 \cdot 3}{7 \cdot 3} - \frac{4}{21} = \frac{12}{21} - \frac{4}{21} = \frac{12 - 4}{21} = \frac{8}{21}\]
29) \[\frac{3}{5} - \frac{11}{20} = \frac{3 \cdot 4}{5 \cdot 4} - \frac{11}{20} = \frac{12}{20} - \frac{11}{20} = \frac{12 - 11}{20} = \frac{1}{20}\]
30) \[\frac{3}{5} - \frac{8}{15} = \frac{3 \cdot 3}{5 \cdot 3} - \frac{8}{15} = \frac{9}{15} - \frac{8}{15} = \frac{9 - 8}{15} = \frac{1}{15}\]
31) \[\frac{21}{27} - \frac{2}{3} = \frac{21}{27} - \frac{2 \cdot 9}{3 \cdot 9} = \frac{21}{27} - \frac{18}{27} = \frac{21 - 18}{27} = \frac{3}{27} = \frac{1}{9}\]
32) \[\frac{63}{81} - \frac{6}{9} = \frac{63}{81} - \frac{6 \cdot 9}{9 \cdot 9} = \frac{63}{81} - \frac{54}{81} = \frac{63 - 54}{81} = \frac{9}{81} = \frac{1}{9}\]
33) \[\frac{48}{49} - \frac{4}{7} = \frac{48}{49} - \frac{4 \cdot 7}{7 \cdot 7} = \frac{48}{49} - \frac{28}{49} = \frac{48 - 28}{49} = \frac{20}{49}\]
34) \[\frac{10}{64} - \frac{1}{8} = \frac{10}{64} - \frac{1 \cdot 8}{8 \cdot 8} = \frac{10}{64} - \frac{8}{64} = \frac{10 - 8}{64} = \frac{2}{64} = \frac{1}{32}\]
35) \[\frac{7}{3} - \frac{14}{27} = \frac{7 \cdot 9}{3 \cdot 9} - \frac{14}{27} = \frac{63}{27} - \frac{14}{27} = \frac{63 - 14}{27} = \frac{49}{27}\]
36) \[\frac{8}{10} - \frac{1}{100} = \frac{8 \cdot 10}{10 \cdot 10} - \frac{1}{100} = \frac{80}{100} - \frac{1}{100} = \frac{80 - 1}{100} = \frac{79}{100}\]
37) \[\frac{40}{100} - \frac{1}{5} = \frac{40}{100} - \frac{1 \cdot 20}{5 \cdot 20} = \frac{40}{100} - \frac{20}{100} = \frac{40 - 20}{100} = \frac{20}{100} = \frac{1}{5}\]
38) \[\frac{112}{4} - \frac{10}{100} = \frac{112 \cdot 25}{4 \cdot 25} - \frac{10}{100} = \frac{2800}{100} - \frac{10}{100} = \frac{2800 - 10}{100} = \frac{2790}{100} = 27 \frac{9}{10}\]
39) \[\frac{4}{10} - \frac{100}{4} = \frac{4 \cdot 2}{10 \cdot 2} - \frac{100}{4} = \frac{8}{20} - \frac{100 \cdot 5}{4 \cdot 5} = \frac{8}{20} - \frac{500}{20} = \frac{8 - 500}{20} = \frac{-492}{20} = -24 \frac{12}{20} = -24 \frac{3}{5}\]
40) \[\frac{70}{900} - \frac{210}{450} = \frac{70}{900} - \frac{210 \cdot 2}{450 \cdot 2} = \frac{70}{900} - \frac{420}{900} = \frac{70 - 420}{900} = \frac{-350}{900} = -\frac{35}{90} = -\frac{7}{18}\]
41) \[\frac{13}{900} - \frac{7}{450} = \frac{13}{900} - \frac{7 \cdot 2}{450 \cdot 2} = \frac{13}{900} - \frac{14}{900} = \frac{13 - 14}{900} = -\frac{1}{900}\]
Ответ: Решения представлены выше
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