Ответ:
а) \(4{,}3-2\frac{1}{15}=\frac{43}{10}-\frac{31}{15}=\frac{67}{30}=2\frac{7}{30}\).
б) \(\frac{5}{6}+2{,}25=\frac{5}{6}+\frac{9}{4}=\frac{37}{12}=3\frac{1}{12}\).
в) \(1{,}3\cdot4\frac{1}{6}=\frac{13}{10}\cdot\frac{25}{6}=\frac{65}{12}=5\frac{5}{12}\).
г) \(\frac{5}{16}:0{,}125=\frac{5}{16}:\frac{1}{8}=\frac{5}{2}=2\frac{1}{2}\).
а) \(0{,}48+3\frac{1}{6}:2{,}4=\frac{12}{25}+\frac{19}{6}:\frac{12}{5}=\frac{12}{25}+\frac{95}{72}=\frac{3239}{1800}=1\frac{1439}{1800}\).
б) \((2{,}75+0{,}3\cdot\frac{5}{6})\cdot\frac{2}{3}=(\frac{11}{4}+\frac{1}{4})\cdot\frac{2}{3}=2\).
В скобках: \(2\frac{3}{4}:4-\frac{7}{24}=\frac{11}{16}-\frac{7}{24}=\frac{19}{48}\). Тогда \(6{,}2-3\frac{9}{16}:\frac{19}{48}=\frac{31}{5}-9=-\frac{14}{5}=-2\frac{4}{5}\).
Ответ: 1) а) \(2\frac{7}{30}\); б) \(3\frac{1}{12}\); в) \(5\frac{5}{12}\); г) \(2\frac{1}{2}\). 2) а) \(1\frac{1439}{1800}\); б) 2. 3) \(-2\frac{4}{5}\).
