Решение:
$$(-4 \frac{1}{6} + 2 \frac{1}{3}) - 393,9 : (-130) - 2 \frac{119}{300} = (-\frac{25}{6} + \frac{7}{3}) - (-\frac{3939}{10} : 130) - \frac{719}{300} = (-\frac{25}{6} + \frac{14}{6}) + \frac{3939}{1300} - \frac{719}{300} = -\frac{11}{6} + \frac{3939}{1300} - \frac{719}{300} = -\frac{11 \cdot 650}{6 \cdot 650} + \frac{3939 \cdot 3}{1300 \cdot 3} - \frac{719 \cdot 13}{300 \cdot 13} = -\frac{7150}{3900} + \frac{11817}{3900} - \frac{9347}{3900} = \frac{-7150 + 11817 - 9347}{3900} = \frac{-4680}{3900} = -\frac{468}{390} = -\frac{234}{195} = -\frac{78}{65} = -\frac{6}{5} = -1,2$$
Ответ: -1,2