Найдите значение произведения: a) $$-2\frac{1}{3} \cdot (-\frac{9}{7})$$; б) $$6\frac{1}{4} \cdot (-1\frac{3}{5})$$; в) $$-3\frac{1}{7} \cdot 4\frac{8}{11}$$; г) $$-2\frac{2}{5} \cdot 3,4$$ д) $$2,2 \cdot (-1\frac{3}{7})$$; е) $$-1\frac{7}{9} \cdot (-6,75)$$.

Решим примеры по действиям:

a) $$-2\frac{1}{3} \cdot (-\frac{9}{7}) = -\frac{7}{3} \cdot (-\frac{9}{7}) = \frac{7 \cdot 9}{3 \cdot 7} = \frac{9}{3} = 3$$

б) $$6\frac{1}{4} \cdot (-1\frac{3}{5}) = \frac{25}{4} \cdot (-\frac{8}{5}) = -\frac{25 \cdot 8}{4 \cdot 5} = -\frac{5 \cdot 2}{1 \cdot 1} = -10$$

в) $$-3\frac{1}{7} \cdot 4\frac{8}{11} = -\frac{22}{7} \cdot \frac{52}{11} = -\frac{2 \cdot 52}{7 \cdot 1} = -\frac{104}{7} = -14\frac{6}{7}$$

г) $$-2\frac{2}{5} \cdot 3,4 = -\frac{12}{5} \cdot 3,4 = -\frac{12}{5} \cdot \frac{34}{10} = -\frac{12 \cdot 34}{5 \cdot 10} = -\frac{6 \cdot 34}{5 \cdot 5} = -\frac{204}{25} = -8\frac{4}{25} = -8,16$$

д) $$2,2 \cdot (-1\frac{3}{7}) = \frac{22}{10} \cdot (-\frac{10}{7}) = -\frac{22 \cdot 10}{10 \cdot 7} = -\frac{22}{7} = -3\frac{1}{7}$$

е) $$-1\frac{7}{9} \cdot (-6,75) = -\frac{16}{9} \cdot (-6,75) = \frac{16}{9} \cdot \frac{675}{100} = \frac{16 \cdot 675}{9 \cdot 100} = \frac{16 \cdot 75}{1 \cdot 100} = \frac{4 \cdot 3}{1 \cdot 1} = \frac{12}{1} = 12$$

Ответ: a) $$3$$, б) $$-10$$, в) $$-14\frac{6}{7}$$, г) $$-8,16$$, д) $$-3\frac{1}{7}$$, е) $$12$$.