Решение задания 4.233
Давай найдем разность дробей:
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а) -\(\frac{3}{17}\) - (-\(\frac{9}{17}\)) = -\(\frac{3}{17}\) + \(\frac{9}{17}\) = \(\frac{6}{17}\)
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б) \(\frac{8}{17}\) - \(\frac{3}{17}\) = \(\frac{5}{17}\)
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в) \(\frac{7}{13}\) - \(\frac{1}{13}\) = \(\frac{6}{13}\)
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г) \(\frac{5}{14}\) - \(\frac{3}{7}\) = \(\frac{5}{14}\) - \(\frac{6}{14}\) = -\(\frac{1}{14}\)
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д) 1\(\frac{1}{4}\) - \(\frac{4}{5}\) = \(\frac{5}{4}\) - \(\frac{4}{5}\) = \(\frac{25}{20}\) - \(\frac{16}{20}\) = \(\frac{9}{20}\)
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e) -\(\frac{2}{3}\) - (-\(\frac{5}{6}\)) = -\(\frac{4}{6}\) + \(\frac{5}{6}\) = \(\frac{1}{6}\)
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ж) 3\(\frac{2}{11}\) - 4\(\frac{7}{33}\) = \(\frac{35}{11}\) - \(\frac{139}{33}\) = \(\frac{105}{33}\) - \(\frac{139}{33}\) = -\(\frac{34}{33}\) = -1\(\frac{1}{33}\)
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з) \(\frac{3}{8}\) - \(\frac{5}{12}\) = \(\frac{9}{24}\) - \(\frac{10}{24}\) = -\(\frac{1}{24}\)
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и) -\(\frac{3}{4}\) - (-\(\frac{4}{9}\)) = -\(\frac{27}{36}\) + \(\frac{16}{36}\) = -\(\frac{11}{36}\)
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к) -4\(\frac{4}{9}\) - (-\(\frac{35}{6}\)) = -\(\frac{40}{9}\) + \(\frac{23}{6}\) = -\(\frac{80}{18}\) + \(\frac{69}{18}\) = -\(\frac{11}{18}\)
Ответ:
- \(\frac{6}{17}\)
- \(\frac{5}{17}\)
- \(\frac{6}{13}\)
- -\(\frac{1}{14}\)
- \(\frac{9}{20}\)
- \(\frac{1}{6}\)
- -1\(\frac{1}{33}\)
- -\(\frac{1}{24}\)
- -\(\frac{11}{36}\)
- -\(\frac{11}{18}\)
Ты отлично справляешься с вычитанием дробей! Продолжай тренироваться, и всё получится!