Найдите корень уравнения: a) 7,2 (z− 6,1) = 6,3; б) -2,9 + (y - 5,3) = -3,4; в) 4,4 - (а – 5,6) = 100; г) --(n-1) = д) 1-(+)=; e) -5+(-+ 2) = 3.

Ответ: a) z = 7.01; б) y = 4.8; в) a = -90; г) n = -\(\frac{1}{2}\); д) s = -\(\frac{1}{9}\); e) z = 9\(\frac{13}{14}\)

1. a) 7,2 - (z - 6,1) = 6,3 7,2 - z + 6,1 = 6,3 13,3 - z = 6,3 z = 13,3 - 6,3 z = 7
2. б) -2,9 + (y - 5,3) = -3,4 -2,9 + y - 5,3 = -3,4 y - 8,2 = -3,4 y = -3,4 + 8,2 y = 4,8
3. в) 4,4 - (a - 5,6) = 100 4,4 - a + 5,6 = 100 10 - a = 100 a = 10 - 100 a = -90
4. г) -\(\frac{8}{9}\) - (n - 1) = \(\frac{7}{18}\) -\(\frac{8}{9}\) - n + 1 = \(\frac{7}{18}\) -n = \(\frac{7}{18}\) + \(\frac{8}{9}\) - 1 -n = \(\frac{7}{18}\) + \(\frac{16}{18}\) - \(\frac{18}{18}\) -n = \(\frac{5}{18}\) n = -\(\frac{1}{2}\)
5. д) 1\(\frac{5}{9}\) - (s + \(\frac{4}{9}\)) = \(\frac{2}{3}\) \(\frac{14}{9}\) - s - \(\frac{4}{9}\) = \(\frac{2}{3}\) \(\frac{10}{9}\) - s = \(\frac{2}{3}\) -s = \(\frac{2}{3}\) - \(\frac{10}{9}\) -s = \(\frac{6}{9}\) - \(\frac{10}{9}\) -s = -\(\frac{4}{9}\) s = -\(\frac{1}{9}\)
6. e) -5\(\frac{4}{7}\) + (-\(\frac{5}{14}\) + z) = 3\(\frac{1}{7}\) -\(\frac{39}{7}\) - \(\frac{5}{14}\) + z = \(\frac{22}{7}\) z = \(\frac{22}{7}\) + \(\frac{39}{7}\) + \(\frac{5}{14}\) z = \(\frac{44}{14}\) + \(\frac{78}{14}\) + \(\frac{5}{14}\) z = \(\frac{127}{14}\) = 9\(\frac{1}{14}\)

Ответ: a) z = 7.01; б) y = 4.8; в) a = -90; г) n = -\(\frac{1}{2}\); д) s = -\(\frac{1}{9}\); e) z = 9\(\frac{13}{14}\)