4.333 Найдите частное: a) $$\frac{6}{11} : (-1\frac{4}{11})$$; б) $$-1\frac{2}{9} : 3\frac{2}{3}$$; в) $$-1\frac{1}{6} : (-\frac{1}{2})$$; г) -0,18: (-2$$\frac{2}{5}$$); д) 0,1 : ($$\frac{-1}{23}$$); e) -$$\frac{3}{7} : 2,4$$.

a) \(\frac{6}{11} : (-1\frac{4}{11}) = \frac{6}{11} : (-\frac{15}{11}) = \frac{6}{11} \cdot (-\frac{11}{15}) = -\frac{6}{15} = -\frac{2}{5} = -0.4\) б) \(-1\frac{2}{9} : 3\frac{2}{3} = -\frac{11}{9} : \frac{11}{3} = -\frac{11}{9} \cdot \frac{3}{11} = -\frac{3}{9} = -\frac{1}{3}\) в) \(-1\frac{1}{6} : (-\frac{1}{2}) = -\frac{7}{6} : (-\frac{1}{2}) = \frac{7}{6} \cdot 2 = \frac{14}{6} = \frac{7}{3} = 2\frac{1}{3}\) г) \(-0.18 : (-2\frac{2}{5}) = -\frac{18}{100} : (-\frac{12}{5}) = \frac{18}{100} \cdot \frac{5}{12} = \frac{18 \cdot 5}{100 \cdot 12} = \frac{90}{1200} = \frac{3}{40} = 0.075\) д) \(0.1 : (-\frac{1}{23}) = \frac{1}{10} : (-\frac{1}{23}) = \frac{1}{10} \cdot (-23) = -\frac{23}{10} = -2.3\) e) \(-\frac{3}{7} : 2.4 = -\frac{3}{7} : \frac{24}{10} = -\frac{3}{7} \cdot \frac{10}{24} = -\frac{30}{168} = -\frac{5}{28} \approx -0.1786\)