26. Найди значение суммы или разности. A 1 3+ 6= 1 1+ 23 31 -= 5 10 1 5 += 12 6 1 1 += 3 4 12 += 3 5 1 1 -= 2 4 8 -1 = 7 11 -= 4 5 13 += 27 31 -= 48 11 += 56 42 += 15 5 71 -= 10 2 1 3=

Решим примеры из столбика А:

1. $$1\frac{1}{3} + \frac{1}{6} = \frac{4}{3} + \frac{1}{6} = \frac{4 \cdot 2}{3 \cdot 2} + \frac{1}{6} = \frac{8}{6} + \frac{1}{6} = \frac{9}{6} = \frac{3}{2} = 1\frac{1}{2}$$
2. $$1\frac{1}{2} + \frac{1}{3} = \frac{3}{2} + \frac{1}{3} = \frac{3 \cdot 3}{2 \cdot 3} + \frac{1 \cdot 2}{3 \cdot 2} = \frac{9}{6} + \frac{2}{6} = \frac{11}{6} = 1\frac{5}{6}$$
3. $$3\frac{3}{5} - \frac{1}{10} = \frac{18}{5} - \frac{1}{10} = \frac{18 \cdot 2}{5 \cdot 2} - \frac{1}{10} = \frac{36}{10} - \frac{1}{10} = \frac{35}{10} = \frac{7}{2} = 3\frac{1}{2}$$
4. $$\frac{1}{12} + \frac{5}{6} = \frac{1}{12} + \frac{5 \cdot 2}{6 \cdot 2} = \frac{1}{12} + \frac{10}{12} = \frac{11}{12}$$
5. $$1\frac{1}{3} + \frac{1}{4} = \frac{4}{3} + \frac{1}{4} = \frac{4 \cdot 4}{3 \cdot 4} + \frac{1 \cdot 3}{4 \cdot 3} = \frac{16}{12} + \frac{3}{12} = \frac{19}{12} = 1\frac{7}{12}$$
6. $$\frac{1}{3} + \frac{2}{5} = \frac{1 \cdot 5}{3 \cdot 5} + \frac{2 \cdot 3}{5 \cdot 3} = \frac{5}{15} + \frac{6}{15} = \frac{11}{15}$$
7. $$1\frac{1}{2} - \frac{1}{4} = \frac{3}{2} - \frac{1}{4} = \frac{3 \cdot 2}{2 \cdot 2} - \frac{1}{4} = \frac{6}{4} - \frac{1}{4} = \frac{5}{4} = 1\frac{1}{4}$$
8. $$8\frac{8}{7} - 1 = \frac{64}{7} - 1 = \frac{64}{7} - \frac{7}{7} = \frac{57}{7} = 8\frac{1}{7}$$
9. $$1\frac{1}{4} - \frac{1}{5} = \frac{5}{4} - \frac{1}{5} = \frac{5 \cdot 5}{4 \cdot 5} - \frac{1 \cdot 4}{5 \cdot 4} = \frac{25}{20} - \frac{4}{20} = \frac{21}{20} = 1\frac{1}{20}$$
10. $$1\frac{1}{2} + \frac{3}{7} = \frac{3}{2} + \frac{3}{7} = \frac{3 \cdot 7}{2 \cdot 7} + \frac{3 \cdot 2}{7 \cdot 2} = \frac{21}{14} + \frac{6}{14} = \frac{27}{14} = 1\frac{13}{14}$$
11. $$\frac{3}{4} - \frac{1}{8} = \frac{3 \cdot 2}{4 \cdot 2} - \frac{1}{8} = \frac{6}{8} - \frac{1}{8} = \frac{5}{8}$$
12. $$1\frac{1}{5} + \frac{1}{6} = \frac{6}{5} + \frac{1}{6} = \frac{6 \cdot 6}{5 \cdot 6} + \frac{1 \cdot 5}{6 \cdot 5} = \frac{36}{30} + \frac{5}{30} = \frac{41}{30} = 1\frac{11}{30}$$
13. $$\frac{4}{15} + \frac{2}{5} = \frac{4}{15} + \frac{2 \cdot 3}{5 \cdot 3} = \frac{4}{15} + \frac{6}{15} = \frac{10}{15} = \frac{2}{3}$$
14. $$7\frac{7}{10} - \frac{1}{2} = \frac{77}{10} - \frac{1}{2} = \frac{77}{10} - \frac{1 \cdot 5}{2 \cdot 5} = \frac{77}{10} - \frac{5}{10} = \frac{72}{10} = \frac{36}{5} = 7\frac{1}{5}$$
15. $$\frac{1}{3} = \frac{1}{3}$$

Ответ: 1) $$1\frac{1}{2}$$; 2) $$1\frac{5}{6}$$; 3) $$3\frac{1}{2}$$; 4) $$\frac{11}{12}$$; 5) $$1\frac{7}{12}$$; 6) $$\frac{11}{15}$$; 7) $$1\frac{1}{4}$$; 8) $$8\frac{1}{7}$$; 9) $$1\frac{1}{20}$$; 10) $$1\frac{13}{14}$$; 11) $$\frac{5}{8}$$; 12) $$1\frac{11}{30}$$; 13) $$\frac{2}{3}$$; 14) $$7\frac{1}{5}$$; 15) $$\frac{1}{3}$$