90. Написать числа, которые в 3 раза меньше каждого из данных: \(\frac{1}{2}, \frac{1}{4}, \frac{1}{6}, \frac{1}{8}, \frac{1}{12}, \frac{3}{5}, \frac{3}{10}, \frac{2}{9}, \frac{2}{15}, \frac{6}{7}, \frac{9}{11}, \frac{45}{93}\)

Пошаговое решение:

Умножаем знаменатель каждой дроби на 3:

• \(\frac{1}{2 \cdot 3} = \frac{1}{6}\)
• \(\frac{1}{4 \cdot 3} = \frac{1}{12}\)
• \(\frac{1}{6 \cdot 3} = \frac{1}{18}\)
• \(\frac{1}{8 \cdot 3} = \frac{1}{24}\)
• \(\frac{1}{12 \cdot 3} = \frac{1}{36}\)
• \(\frac{3}{5 \cdot 3} = \frac{3}{15} = \frac{1}{5}\)
• \(\frac{3}{10 \cdot 3} = \frac{3}{30} = \frac{1}{10}\)
• \(\frac{2}{9 \cdot 3} = \frac{2}{27}\)
• \(\frac{2}{15 \cdot 3} = \frac{2}{45}\)
• \(\frac{6}{7 \cdot 3} = \frac{6}{21} = \frac{2}{7}\)
• \(\frac{9}{11 \cdot 3} = \frac{9}{33} = \frac{3}{11}\)
• \(\frac{45}{93 \cdot 3} = \frac{45}{279} = \frac{15}{93} = \frac{5}{31}\)

Ответ: \(\frac{1}{6}, \frac{1}{12}, \frac{1}{18}, \frac{1}{24}, \frac{1}{36}, \frac{1}{5}, \frac{1}{10}, \frac{2}{27}, \frac{2}{45}, \frac{2}{7}, \frac{3}{11}, \frac{5}{31}\)