Вопрос:

Квадратные уравнения

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Ответ:

2x²+3x-5=0 x² + 2x = 16x-49 2x²-5x+3 = 0 x² + 7x + 12 = 0 x² = 10x - 16
3x² + 5x-2= 0 5x² + 1 = 6x-4x² x² + 3x + 2 = 0 2x²-9x + 4 = 0 x² = 2x
3x²+2x-5 = 0 x(x + 2) = 3 2x²-9x + 4 = 0 x²-10x + 16 = 0 (x-3)² = 9-x²
6x²+x-1=0 x(x - 5) = -4 3x²+8x-3=0 3x²-2x - 1 = 0 4-x² = (2 + x)²
x²-5x-6 = 0 x² + 3 = 3 - x -x² + 7x - 10 = 0 2x²-3x-5=0 2x²-7x+5=0
3x² + 7x-6=0 5x²-7x + 2 = 0 4x² + 4x + 1 = 0 3x²-4x + 1 = 0 2x²+3x-14 = 0
2x² + 3x-2=0 2x²-7x + 3 = 0 x²-6x-16 = 0 -x²+3x+4=0 x² = 4x
-x²+2x+8=0 5x²-3x-2=0 x²+2x-15 = 0 x²-6x-27 = 0 x²-2010x - 2011 = 0
x²+10x + 21 = 0 2x²+3-7x 6x²-7x + 1 = 0 x² + 3x - 18 = 0 (2x-5)² - 4x² = 0
x²-8x + 7 = 0 x(x - 4) = -3 7x² + 9x + 2 = 0 x² + 8 = 6x x² - 5x = 0
x²-7x-8=0 x(x + 3) = 4 x² + 4x - 45 = 0 x² + 11x = -28 x² - x = 0
5x²-8x-4 = 0 x² + 2 = x + 2 x²+x-6 = 0 x²-9x = -18 x² - 9 = 0
5x²-8x+3=0 3x² + 9 = 12x - x² x² + 3x + 2 = 0 x² = 17x - 72 x² - 4 = 0
5x + 2 = 2-2x² x² + 4 = 5x x² + 4x - 5 = 0 6x²-7x + 2 = 0 x² = 16
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