г) Выполним вычисления:
$$\frac{27}{34} \cdot (5 - 2 \frac{4}{5} \cdot 1 \frac{1}{9}) = \frac{27}{34} \cdot (5 - \frac{2 \cdot 5 + 4}{5} \cdot \frac{1 \cdot 9 + 1}{9}) = \frac{27}{34} \cdot (5 - \frac{14}{5} \cdot \frac{10}{9}) = \frac{27}{34} \cdot (5 - \frac{14 \cdot 10}{5 \cdot 9}) = \frac{27}{34} \cdot (5 - \frac{14 \cdot 2}{1 \cdot 9}) = \frac{27}{34} \cdot (5 - \frac{28}{9}) = \frac{27}{34} \cdot (\frac{5 \cdot 9 - 28}{9}) = \frac{27}{34} \cdot (\frac{45 - 28}{9}) = \frac{27}{34} \cdot \frac{17}{9} = \frac{27 \cdot 17}{34 \cdot 9} = \frac{3 \cdot 1}{2 \cdot 1} = \frac{3}{2} = 1 \frac{1}{2}.$$
Ответ: $$1\frac{1}{2}$$