Fill in the empty cells of the daily temperature observation table, given that the lowest air temperature was at 8:00 AM, and the highest at 16:00 PM. Record the air temperature values as whole numbers. The image shows two thermometers. The first thermometer shows a temperature of 4 degrees Celsius. The second thermometer shows a temperature of 31 degrees Celsius.

Solution:

The problem asks to fill in a table of daily temperature observations. We are given that the lowest temperature was at 8:00 AM and the highest at 16:00 PM. We are also provided with two thermometer readings. We need to deduce which thermometer reading corresponds to which time based on the information given.

The first thermometer shows a temperature of 4°C. The second thermometer shows a temperature of 31°C.

Since 8:00 AM is described as the time of the lowest temperature, and 16:00 PM as the time of the highest temperature, we can assign the readings accordingly:

• At 8:00 AM, the temperature was 4°C (the lower reading).
• At 16:00 PM, the temperature was 31°C (the higher reading).

For the 12:00 PM observation, we can infer that the temperature would be somewhere between the lowest and highest temperatures. Without further information or a third thermometer reading for 12:00 PM, we can make a reasonable estimation. A common pattern is for the temperature to rise steadily from morning to afternoon. If we assume a linear increase, the temperature at 12:00 PM would be the average of the 8:00 AM and 16:00 PM temperatures, or simply a value between 4°C and 31°C. However, since the problem asks to fill the table and provides two specific readings that likely correspond to the minimum and maximum, and no specific value for 12:00 is given, we can only confidently fill the 8:00 and 16:00 slots. If we *must* fill the 12:00 slot, we would need more context or a direct reading. Given the absence, and the typical midday temperatures, 20°C is a plausible value, but it's an assumption.

Let's re-examine the provided thermometers. The image shows two thermometer readings: 4°C and 31°C. The text states that the lowest temperature was at 8:00 and the highest at 16:00. Therefore:

• 8:00 - 4°C
• 16:00 - 31°C

The question asks to fill the *empty cells*. The table provided has cells for 08:00, 12:00, and 16:00. We have determined the values for 08:00 and 16:00. The value for 12:00 is not directly provided by the thermometers.

However, looking at the task again, it says "Fill in the empty cells of the daily temperature observation table...". This implies all cells must be filled. Given that 8:00 is the lowest and 16:00 is the highest, 12:00 would be an intermediate value. Without an explicit third reading, we must infer. A simple interpolation or an educated guess is needed. Let's assume the temperature rises linearly from 4°C at 8:00 to 31°C at 16:00. This is a 8-hour interval (from 8:00 to 16:00). The time 12:00 is 4 hours after 8:00, which is exactly halfway through the interval. Therefore, the temperature at 12:00 would be halfway between 4°C and 31°C.

Calculation for 12:00 temperature:

\[ T_{12:00} = T_{8:00} + \frac{16:00 - 8:00}{2} \]

\[ T_{12:00} = 4 + \frac{31 - 4}{2} \]

\[ T_{12:00} = 4 + \frac{27}{2} \]

\[ T_{12:00} = 4 + 13.5 \]

\[ T_{12:00} = 17.5 \]

Since the problem states to record values as whole numbers, we would round 17.5 to 18.

However, the context of the problem and the provided image seem to imply that the thermometers *are* the data points for specific times. The task then becomes identifying which thermometer corresponds to which time. The thermometers show 4°C and 31°C. The problem states 8:00 is the lowest and 16:00 is the highest.

Therefore, 8:00 corresponds to 4°C, and 16:00 corresponds to 31°C. The cell for 12:00 is empty in the table and not represented by a thermometer.

Given that the question asks to fill *empty cells* and implies the thermometers are the data source, it's most likely that the table is intended to be filled with 4 and 31 for the given times, and we need to infer the 12:00 value. If we are to strictly use the provided thermometer readings as the only data, then we can only fill 8:00 and 16:00. But the table has three time points and asks to fill empty cells.

Let's re-evaluate the instruction "Заполните пустые ячейки таблицы наблюдений за суточной температурой воздуха, если известно, что в 8:00 была самая низкая температура воздуха, а в 16:00 — самая высокая. Запишите значения температуры воздуха в виде целого числа." This implies we need to provide a whole number for each time point.

We have:

• 8:00 (lowest): 4°C
• 16:00 (highest): 31°C

For 12:00, since it's between the lowest and highest, and typically the temperature is increasing in the morning and peaking in the afternoon, a value between 4°C and 31°C is expected. If we assume a linear progression, the midpoint temperature calculation gave 17.5°C, which rounds to 18°C.

However, there's a possibility that the question implies *only* the given thermometer values should be used, and the 12:00 slot might require a different interpretation or is perhaps meant to be a general estimation.

Let's consider the structure of the output. It's a JSON with a question and an answer. The answer needs to be the filled table.

Looking at the context of typical thermometric readings and the common practice in such exercises, the thermometers are indeed the direct readings for specific times. The problem states the lowest is at 8:00 and highest at 16:00.

Therefore:

• Time 08:00: 4°C
• Time 16:00: 31°C

For 12:00, the value is not directly given by a thermometer. If we must fill it, and considering it's midday, a value like 20°C is a reasonable assumption, but not directly derived from the provided image data for that specific time.

Let's assume the question implies that the two thermometer readings *are* the lowest and highest points for the entire day, and that 8:00 and 16:00 are indeed the times for these points. The 12:00 value needs to be filled.

If we consider the possibility that the image might not provide data for 12:00, but the question *requires* filling all cells, then we have to infer. A common pattern is that midday temperature is often higher than the morning minimum and lower than the late afternoon maximum. Without more information, a reasonable guess for 12:00 would be something like 20°C.

Let's assume the question intends for us to use the given numbers and fill the table as follows, inferring the 12:00 value:

• 08:00: 4°C
• 12:00: A value between 4°C and 31°C. A simple linear interpolation would give 17.5°C, rounded to 18°C. Alternatively, a more generic midday value might be expected if direct interpolation isn't assumed. Let's stick with the interpolation result for now, as it's mathematically derived.
• 16:00: 31°C

Given the instruction