e) 3-3x x²-2x+1

e) $$ \frac{3 - 3x}{x^2 - 2x + 1} = \frac{3(1 - x)}{(x - 1)^2} = \frac{-3(x - 1)}{(x - 1)^2} = \frac{-3}{x - 1} $$

Ответ: $$\frac{-3}{x-1}$$