e) $$\frac{4}{9}x \cdot (-\frac{5}{16}y) \cdot \frac{9}{5}p = $$

Решение:

$$\frac{4}{9}x \cdot (-\frac{5}{16}y) \cdot \frac{9}{5}p = -\frac{4 \cdot 5 \cdot 9}{9 \cdot 16 \cdot 5}xyp = -\frac{180}{720}xyp = -\frac{1}{4}xyp$$

Ответ: $$-\frac{1}{4}xyp$$