в) $$\frac{7}{9}+3=\frac{7+3\cdot 9}{9}=\frac{7+27}{9}=\frac{34}{9}=3\frac{7}{9}$$
$$1-\frac{3}{5}=\frac{5}{5}-\frac{3}{5}=\frac{2}{5}$$
$$1-\frac{7}{8}=\frac{8}{8}-\frac{7}{8}=\frac{1}{8}$$
Ответ: $$\frac{34}{9}; \frac{2}{5}; \frac{1}{8}$$