736d4c52bd1f42cd84e8f7574... Арифметика 5-6 классы

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736d4c52bd1f42cd84e8f7574... Арифметика 5-6 классы

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Ответ: смотри решение ниже

Краткое пояснение: Решаем примеры на сложение, вычитание, умножение и деление.

6 вариант	7 вариант	8 вариант	9 вариант
1000 + 67 = 1067	1372 + 500 = 1872	42 + 70 = 112	805 + 26 = 831
400 – 34 = 366	150 – 162 = -12	4000 – 29 = 3971	1000 – 123 = 877
8100 : 9 = 900	184 ⋅ 0 = 0	0 : 37 = 0	19 ⋅ 90 = 1710
2,4 ⋅ 0,05 = 0,12	3,2 : 20 = 0,16	7,2 : 1,2 = 6	0,72 : 2,4 = 0,3
1,3 + 4,14 = 5,44	6,2 + 4,09 = 10,29	2,82 + 3,1 = 5,92	5,47 + 38 = 43,47
50,7 ⋅ 0,01 = 0,507	6,21 : 0,01 = 621	0,24 ⋅ 0,01 = 0,0024	20,5 : 0,01 = 2050
6\(\frac{5}{9}\) + 3\(\frac{4}{9}\) = 9\(\frac{9}{9}\) = 10	9\(\frac{1}{9}\) + 7\(\frac{2}{9}\) = 16\(\frac{3}{9}\) = 16\(\frac{1}{3}\)	20\(\frac{7}{8}\) - 8\(\frac{3}{8}\) = 12\(\frac{4}{8}\) = 12\(\frac{1}{2}\)	3\(\frac{3}{8}\) + 6\(\frac{7}{8}\) = 9\(\frac{10}{8}\) = 10\(\frac{2}{8}\) = 10\(\frac{1}{4}\)
\(\frac{1}{2}\) + \(\frac{2}{9}\) = \(\frac{9}{18}\) + \(\frac{4}{18}\) = \(\frac{13}{18}\)	\(\frac{9}{15}\) - \(\frac{3}{5}\) = \(\frac{9}{15}\) - \(\frac{9}{15}\) = 0	\(\frac{5}{14}\) + \(\frac{6}{7}\) = \(\frac{5}{14}\) + \(\frac{12}{14}\) = \(\frac{17}{14}\) = 1\(\frac{3}{14}\)	\(\frac{2}{9}\) + \(\frac{1}{3}\) = \(\frac{2}{9}\) + \(\frac{3}{9}\) = \(\frac{5}{9}\)
6 : \(\frac{3}{11}\) = \(\frac{6}{1}\) ⋅ \(\frac{11}{3}\) = \(\frac{2}{1}\) ⋅ \(\frac{11}{1}\) = 22	\(\frac{9}{22}\) : 6 = \(\frac{9}{22}\) ⋅ \(\frac{1}{6}\) = \(\frac{3}{22}\) ⋅ \(\frac{1}{2}\) = \(\frac{3}{44}\)	2\(\frac{1}{3}\) ⋅ \(\frac{3}{7}\) = \(\frac{7}{3}\) ⋅ \(\frac{3}{7}\) = 1	1\(\frac{1}{6}\) : \(\frac{7}{18}\) = \(\frac{7}{6}\) ⋅ \(\frac{18}{7}\) = \(\frac{1}{1}\) ⋅ \(\frac{3}{1}\) = 3
\(\frac{1}{6}\) + 0,4 = \(\frac{1}{6}\) + \(\frac{4}{10}\) = \(\frac{1}{6}\) + \(\frac{2}{5}\) = \(\frac{5}{30}\) + \(\frac{12}{30}\) = \(\frac{17}{30}\)	4,7 - 4\(\frac{2}{3}\) = 4\(\frac{7}{10}\) - 4\(\frac{2}{3}\) = \(\frac{7}{10}\) - \(\frac{2}{3}\) = \(\frac{21}{30}\) - \(\frac{20}{30}\) = \(\frac{1}{30}\)	0,5 + \(\frac{3}{7}\) = \(\frac{1}{2}\) + \(\frac{3}{7}\) = \(\frac{7}{14}\) + \(\frac{6}{14}\) = \(\frac{13}{14}\)	\(\frac{2}{3}\) + 0,25 = \(\frac{2}{3}\) + \(\frac{1}{4}\) = \(\frac{8}{12}\) + \(\frac{3}{12}\) = \(\frac{11}{12}\)
\(\frac{5}{12}\) : 0,6 = \(\frac{5}{12}\) : \(\frac{6}{10}\) = \(\frac{5}{12}\) ⋅ \(\frac{10}{6}\) = \(\frac{5}{6}\) ⋅ \(\frac{5}{6}\) = \(\frac{25}{36}\)	2\(\frac{1}{3}\) ⋅ 0,3 = \(\frac{7}{3}\) ⋅ \(\frac{3}{10}\) = \(\frac{7}{1}\) ⋅ \(\frac{1}{10}\) = \(\frac{7}{10}\)	2\(\frac{1}{3}\) : 0,7 = \(\frac{7}{3}\) : \(\frac{7}{10}\) = \(\frac{7}{3}\) ⋅ \(\frac{10}{7}\) = \(\frac{1}{3}\) ⋅ \(\frac{10}{1}\) = \(\frac{10}{3}\) = 3\(\frac{1}{3}\)	0,3 ⋅ 2\(\frac{2}{3}\) = \(\frac{3}{10}\) ⋅ \(\frac{8}{3}\) = \(\frac{1}{5}\) ⋅ \(\frac{4}{1}\) = \(\frac{4}{5}\)

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