дание 1. Найдите значение выражения 3 1 1 1) ( +1 ): ; 2) ( -2 ): 48:3) 28 - 35 16 5 32' 8 20 1 91

Решение:

1. $$\left(\frac{3}{16}+1\frac{1}{5}\right):\frac{1}{32}=\left(\frac{3}{16}+\frac{6}{5}\right):\frac{1}{32}=\left(\frac{3 \cdot 5}{16 \cdot 5}+\frac{6 \cdot 16}{5 \cdot 16}\right):\frac{1}{32}=\left(\frac{15}{80}+\frac{96}{80}\right):\frac{1}{32}=\frac{111}{80}:\frac{1}{32}=\frac{111}{80} \cdot \frac{32}{1}=\frac{111 \cdot 32}{80 \cdot 1}=\frac{111 \cdot 4}{10 \cdot 1}=\frac{444}{10}=44,4$$

   Ответ: 44,4

2. $$\left(\frac{7}{8}-2\frac{3}{20}\right):\frac{1}{48}=\left(\frac{7}{8}-\frac{43}{20}\right):\frac{1}{48}=\left(\frac{7 \cdot 5}{8 \cdot 5}-\frac{43 \cdot 2}{20 \cdot 2}\right):\frac{1}{48}=\left(\frac{35}{40}-\frac{86}{40}\right):\frac{1}{48}=-\frac{51}{40}:\frac{1}{48}=-\frac{51}{40} \cdot \frac{48}{1}=-\frac{51 \cdot 48}{40 \cdot 1}=-\frac{51 \cdot 6}{5 \cdot 1}=-\frac{306}{5}=-61,2$$

   Ответ: -61,2

3. $$\frac{\frac{1}{28}-\frac{1}{35}}{\frac{1}{91}}=\frac{\frac{1 \cdot 5}{28 \cdot 5}-\frac{1 \cdot 4}{35 \cdot 4}}{\frac{1}{91}}=\frac{\frac{5}{140}-\frac{4}{140}}{\frac{1}{91}}=\frac{\frac{1}{140}}{\frac{1}{91}}=\frac{1}{140}:\frac{1}{91}=\frac{1}{140} \cdot \frac{91}{1}=\frac{91}{140}=\frac{13 \cdot 7}{20 \cdot 7}=\frac{13}{20}=0,65$$

   Ответ: 0,65