cosα=√2/2 find tgα=?

Ответ: 1

\[\cos \alpha = \frac{\sqrt{2}}{2}\] \(\alpha = \frac{\pi}{4}\) \[\sin \frac{\pi}{4} = \frac{\sqrt{2}}{2}\] \[tg \alpha = \frac{\sin \alpha}{\cos \alpha} = \frac{\frac{\sqrt{2}}{2}}{\frac{\sqrt{2}}{2}} = 1\]

Ответ: 1