B-T ) проставьте в виде многочина 1) (CC-6)2 3) (5-8) (5+a) 2) (29-38)2 4) (7x+10g) (10g-7x) Разлошите на мношите 3) Pajuou 1802-49 3) 100-9x2 5 3 2) c2-80+16 4) 40-42008-2582 6) 49xty-ys 7) a4-1 3) Упростить u 1) (x-2)(x+2)-(x-5)2 8)-702+140-7 найти чити значени x=0,20 2) (3-6)(3+8)(9+82)+(4+82)2, B-1 5) (3a+1) (9a23a+1), a=3 4) Решите уравнение 1) 4(3y+1)2-27 = (4y+9)(49-9)+2(5912)(24-7) 2) 2x3-50x=0 3) 16x3+8x2+x=0

\[(c-6)^2 = c^2 - 12c + 36\]

\[(2a-3b)^2 = 4a^2 - 12ab + 9b^2\]

\[(5-a)(5+a) = 25 - a^2\]

\[(7x+10y)(10y-7x) = 100y^2 - 49x^2\]

\[b^2 - 49 = (b - 7)(b + 7)\]

\[c^2 - 8c + 16 = (c - 4)^2\]

\[100 - 9x^2 = (10 - 3x)(10 + 3x)\]

\[4a^2 + 20ab + 25b^2 = (2a + 5b)^2\]

\[b^3 - 8c^3 = (b - 2c)(b^2 + 2bc + 4c^2)\]

\[49x^2y - y^3 = y(49x^2 - y^2) = y(7x - y)(7x + y)\]

\[a^4 - 1 = (a^2 - 1)(a^2 + 1) = (a - 1)(a + 1)(a^2 + 1)\]

\[-7a^2 + 14a - 7 = -7(a^2 - 2a + 1) = -7(a - 1)^2\]

\[(x-2)(x+2) - (x-5)^2 = x^2 - 4 - (x^2 - 10x + 25) = 10x - 29\]

При \[x = 0.2\]: \[10(0.2) - 29 = 2 - 29 = -27\]

\[(3-b)(3+b)(9+b^2) + (4+b^2)^2 = (9 - b^2)(9 + b^2) + (16 + 8b^2 + b^4) = 81 - b^4 + 16 + 8b^2 + b^4 = 97 + 8b^2\]

При \[b = \frac{1}{2}\]: \[97 + 8(\frac{1}{2})^2 = 97 + 8(\frac{1}{4}) = 97 + 2 = 99\]

\[(3a+1)(9a^2-3a+1) = 27a^3 + 1\]

При \[a = \frac{1}{3}\]: \[27(\frac{1}{3})^3 + 1 = 27(\frac{1}{27}) + 1 = 1 + 1 = 2\]

\[4(3y+1)^2 - 27 = (4y+9)(4y-9) + 2(5y+2)(2y-7)\]

\[4(9y^2 + 6y + 1) - 27 = 16y^2 - 81 + 2(10y^2 - 31y - 14)\]

\[36y^2 + 24y + 4 - 27 = 16y^2 - 81 + 20y^2 - 62y - 28\]

\[36y^2 + 24y - 23 = 36y^2 - 62y - 109\]

\[24y + 62y = -109 + 23\]

\[86y = -86\]

\[y = -1\]

\[2x^3 - 50x = 0\]

\[2x(x^2 - 25) = 0\]

\[2x(x - 5)(x + 5) = 0\]

\[x = 0, x = 5, x = -5\]

\[16x^3 + 8x^2 + x = 0\]

\[x(16x^2 + 8x + 1) = 0\]

\[x(4x + 1)^2 = 0\]

\[x = 0, x = -\frac{1}{4}\]