Ответ: смотри решение ниже
a) 23 ⋅ (-6) + 27 ⋅ (-6) = -6 ⋅ (23 + 27) = -6 ⋅ 50 = -300
б) -1\(\frac{1}{6}\) ⋅ 6 - 1\(\frac{1}{6}\) ⋅ 9 - 1\(\frac{1}{6}\) ⋅ 3 = -1\(\frac{1}{6}\) ⋅ (6 + 9 + 3) = -\(\frac{7}{6}\) ⋅ 18 = -\(\frac{7 \cdot 18}{6}\) = -\(\frac{7 \cdot 3}{1}\) = -21
в) -4\(\frac{1}{7}\) + 4,8 - 6\(\frac{6}{7}\) = -4\(\frac{1}{7}\) - 6\(\frac{6}{7}\) + 4,8 = -10\(\frac{1}{7}\) + 4,8 = -10\(\frac{1}{7}\) + \(\frac{48}{10}\) = -\(\frac{71}{7}\) + \(\frac{24}{5}\) = -\(\frac{71 \cdot 5}{7 \cdot 5}\) + \(\frac{24 \cdot 7}{5 \cdot 7}\) = -\(\frac{355}{35}\) + \(\frac{168}{35}\) = -\(\frac{187}{35}\) = -5\(\frac{12}{35}\)
а) -3,75 ⋅ 0 = 0; 24 ⋅ 1 = 24; 0 < 24, значит -3,75 ⋅ 0 < 24 ⋅ 1
б) -3\(\frac{7}{8}\) ⋅ 12 = -\(\frac{31}{8}\) ⋅ 12 = -\(\frac{31 \cdot 12}{8}\) = -\(\frac{31 \cdot 3}{2}\) = -\(\frac{93}{2}\) = -46,5
-12 ⋅ 3\(\frac{7}{8}\) = -12 ⋅ \(\frac{31}{8}\) = -\(\frac{12 \cdot 31}{8}\) = -\(\frac{3 \cdot 31}{2}\) = -\(\frac{93}{2}\) = -46,5
-46,5 = -46,5, значит -3\(\frac{7}{8}\) ⋅ 12 = -12 ⋅ 3\(\frac{7}{8}\)
(-18,4 + 3,16) + 12,47 = -15,24 + 12,47 = -2,77
а) \(\frac{23}{-24}\) = -\(\frac{23}{24}\)
б) \(\frac{-12}{-25}\) = \(\frac{12}{25}\)
в) \(\frac{33}{-35}\) = -\(\frac{33}{35}\)
г) \(\frac{-45}{-49}\) = \(\frac{45}{49}\)
(
-\(\frac{5}{12}\) + \(\frac{11}{16}
) : (-\(\frac{13}{72}\)) = (-\(\frac{5 \cdot 4}{12 \cdot 4}\) + \(\frac{11 \cdot 3}{16 \cdot 3}\)) : (-\(\frac{13}{72}\)) = (-\(\frac{20}{48}\) + \(\frac{33}{48}\)) : (-\(\frac{13}{72}\)) = \(\frac{13}{48}\) : (-\(\frac{13}{72}\)) = \(\frac{13}{48}\) ⋅ (-\(\frac{72}{13}\)) = -\(\frac{13 \cdot 72}{48 \cdot 13}\) = -\(\frac{72}{48}\) = -\(\frac{3}{2}\) = -1\(\frac{1}{2}\)
Ответ: смотри решение выше
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