We are given that \( a = -\frac{1}{3} \) and we need to find the value of \( a + a^2 \).
First, let's calculate \( a^2 \):
\[ a^2 = \left(-\frac{1}{3}\right)^2 = \left(-\frac{1}{3}\right) \times \left(-\frac{1}{3}\right) = \frac{1}{9} \]
Now, substitute the values of 'a' and 'a²' into the expression \( a + a^2 \):
\[ a + a^2 = \left(-\frac{1}{3}\right) + \frac{1}{9} \]
To add these fractions, we find a common denominator, which is 9:
\[ -\frac{1}{3} = -\frac{1 \cdot 3}{3 \cdot 3} = -\frac{3}{9} \]
So, the expression becomes:
\[ -\frac{3}{9} + \frac{1}{9} = \frac{-3 + 1}{9} = \frac{-2}{9} \]
Ответ: -2/9