Ответ:
Преобразуем смешанные числа и десятичные дроби:
\(8\frac{7}{12}=\frac{313}{36}\), \(2\frac{17}{36}=\frac{89}{36}\), \(2,7=\frac{27}{10}\), \(4\frac{1}{3}=\frac{13}{3}\), \(0,65=\frac{13}{20}\).
Тогда:
\[\left(\frac{313}{36}-\frac{89}{36}\right)\cdot\frac{27}{10}-\frac{13}{3}:\frac{13}{20}=\frac{224}{36}\cdot\frac{27}{10}-\frac{13}{3}\cdot\frac{20}{13}.\]
\[\frac{224}{36}\cdot\frac{27}{10}=\frac{56}{9}\cdot\frac{27}{10}=\frac{84}{5},\qquad \frac{13}{3}\cdot\frac{20}{13}=\frac{20}{3}.\]
\[\frac{84}{5}-\frac{20}{3}=\frac{252-100}{15}=\frac{152}{15}=10\frac{2}{15}.\]
Ответ: \(10\frac{2}{15}\).
