A. Сложение и вычитание дробей с одинаковыми знаменателями
Задание 6. Выполните действие:
- \( \frac{1}{7} + \frac{3}{7} = \frac{1+3}{7} = \frac{4}{7} \)
- \( \frac{2}{3} + \frac{x}{3} = \frac{2+x}{3} \)
- \( \frac{3a}{7} + \frac{3+a}{7} = \frac{3a+3+a}{7} = \frac{4a+3}{7} \)
- \( \frac{2+x}{4} + \frac{2+x}{4} = \frac{2+x+2+x}{4} = \frac{4+2x}{4} = \frac{2(2+x)}{4} = \frac{2+x}{2} \)
- \( \frac{1+2x}{10} + \frac{1+2x}{10} = \frac{1+2x+1+2x}{10} = \frac{2+4x}{10} = \frac{2(1+2x)}{10} = \frac{1+2x}{5} \)
- \( \frac{x-2}{5} - \frac{x-2}{5} = \frac{(x-2)-(x-2)}{5} = \frac{x-2-x+2}{5} = \frac{0}{5} = 0 \)
- \( \frac{a}{3} + \frac{b}{3} = \frac{a+b}{3} \)
- \( \frac{2a}{11} + \frac{b}{11} = \frac{2a+b}{11} \)
- \( \frac{y^2}{8} - \frac{1}{8} = \frac{y^2-1}{8} \)
- \( \frac{6}{x} + \frac{2}{x} = \frac{6+2}{x} = \frac{8}{x} \)
- \( \frac{3a}{4} - \frac{4}{4} = \frac{3a-4}{4} \)
- \( \frac{2x^2}{y^3} + \frac{x}{y^3} = \frac{2x^2+x}{y^3} \)
- \( \frac{5b}{a^2} - \frac{3b}{a^2} = \frac{5b-3b}{a^2} = \frac{2b}{a^2} \)
- \( \frac{x}{2y} - \frac{a}{2y} = \frac{x-a}{2y} \)
- \( \frac{-2a}{b^2} + \frac{a}{b^2} = \frac{-2a+a}{b^2} = \frac{-a}{b^2} \)
- \( \frac{3a^3+x}{4a} - \frac{5x-2a^3}{4a} = \frac{3a^3+x-(5x-2a^3)}{4a} = \frac{3a^3+x-5x+2a^3}{4a} = \frac{5a^3-4x}{4a} \)