Ответ:
Решение:
Проверим каждое выражение, подставляя значения \( a = 35 \) и \( b = 63 \).
- \( a \% 7 == 0 \) → \( 35 \% 7 == 0 \) → \( 0 == 0 \) → True.
- \( b > 0 \text{ or } a < 0 \text{ or } b < a \text{ and } a > 5 \) → \( 63 > 0 \text{ or } 35 < 0 \text{ or } 63 < 35 \text{ and } 35 > 5 \) → \( True \text{ or } False \text{ or } False \text{ and } True \) → \( True \text{ or } False \) → True.
- \( a \% 5 == 0 \text{ or } b \% 5 == 0 \) → \( 35 \% 5 == 0 \text{ or } 63 \% 5 == 0 \) → \( 0 == 0 \text{ or } 3 == 0 \) → \( True \text{ or } False \) → True.
- \( \text{not} (a + b > 0 \text{ or } a * 7 > a b) \) → \( \text{not} (35 + 63 > 0 \text{ or } 35 * 7 > 35 63) \) → \( \text{not} (98 > 0 \text{ or } 245 > \text{очень большое число}) \) → \( \text{not} (True \text{ or } False) \) → \( \text{not} (True) \) → False.
- \( a \% 9 == 0 \text{ and } b \% 9 == 0 \) → \( 35 \% 9 == 0 \text{ and } 63 \% 9 == 0 \) → \( 8 == 0 \text{ and } 0 == 0 \) → \( False \text{ and } True \) → False.
- \( \text{not} (a > b \text{ and } b > a) \text{ or } b <= 9 \) → \( \text{not} (35 > 63 \text{ and } 63 > 35) \text{ or } 63 <= 9 \) → \( \text{not} (False \text{ and } True) \text{ or } False \) → \( \text{not} (False) \text{ or } False \) → \( True \text{ or } False \) → True.
Ответ: Первое, второе, третье и шестое выражения равны True.
