1) 5a2 – 3b2 + a² + 3b2; 2) 11x3 – 8y² + 2x³ + 8y²; 3) 1,3a – 2,7b2 + 2,7a – 0,3b2; 4) 7,2x3 + 0,8y – 1,2x3 + 2,2y. 1) 1/3 xy – 2y² + 2/3 xy – y² + xy; 2) mn – 2/5 m² + 3mn – 3/5 m² + 2m²; 3) 2cd2 – 2dc2 + 3cd² + 1,1d2c² + 2dc²; 4) 3,7a2b – 3ab + 2ab² – 1,2a2b – 2ab2. 1) x3y² – 2xy² + 3x²y – 2x3y² – 3x²y – xy²; 2) 4mn³ – 5mn + 2m²n³ + mn³ – mn – 2m²n³; 3) ab + ab² + a2b – 2ab – ab² – 2a²b; 4) c³d + cd + cd³ – 3c³d – cd – 3cd³.

Question

Вопрос:

1) 5a2 – 3b2 + a² + 3b2; 2) 11x3 – 8y² + 2x³ + 8y²; 3) 1,3a – 2,7b2 + 2,7a – 0,3b2; 4) 7,2x3 + 0,8y – 1,2x3 + 2,2y. 1) 1/3 xy – 2y² + 2/3 xy – y² + xy; 2) mn – 2/5 m² + 3mn – 3/5 m² + 2m²; 3) 2cd2 – 2dc2 + 3cd² + 1,1d2c² + 2dc²; 4) 3,7a2b – 3ab + 2ab² – 1,2a2b – 2ab2. 1) x3y² – 2xy² + 3x²y – 2x3y² – 3x²y – xy²; 2) 4mn³ – 5mn + 2m²n³ + mn³ – mn – 2m²n³; 3) ab + ab² + a2b – 2ab – ab² – 2a²b; 4) c³d + cd + cd³ – 3c³d – cd – 3cd³.

Смотреть решения всех заданий с листа

Ответ:

ГДЗ по фото 📸

Accepted Answer

Ответ:

1) 6a²

2) 13x³

3) 4a - 3b²

4) 6x³ + 3y

1) (4/3)xy - 3y²

2) 4mn + (3/5)m²

3) 5cd² + 1,1d²c²

4) 2,5a²b

1) -x³y² - 3xy²

2) 5mn³ - 6mn

3) -ab - a²b

4) -2c³d - 2cd³

Краткое пояснение: Чтобы упростить выражение, нужно привести подобные слагаемые.

Решение:

1) 5a² – 3b² + a² + 3b² = (5a² + a²) + (-3b² + 3b²) = 6a²

2) 11x³ – 8y² + 2x³ + 8y² = (11x³ + 2x³) + (-8y² + 8y²) = 13x³

3) 1,3a – 2,7b² + 2,7a – 0,3b² = (1,3a + 2,7a) + (-2,7b² – 0,3b²) = 4a - 3b²

4) 7,2x³ + 0,8y – 1,2x³ + 2,2y = (7,2x³ – 1,2x³) + (0,8y + 2,2y) = 6x³ + 3y

1) \(\frac{1}{3}\) xy – 2y² + \(\frac{2}{3}\) xy – y² + xy = \((\frac{1}{3} + \frac{2}{3} + 1)xy\) + (-2y² - y²) = \((\frac{1+2+3}{3})xy\) - 3y² = \(\frac{6}{3}xy\) - 3y² = (4/3)xy - 3y²

2) mn – \(\frac{2}{5}\) m² + 3mn – \(\frac{3}{5}\) m² + 2m² = (mn + 3mn) + (-\(\frac{2}{5}\) m² – \(\frac{3}{5}\) m² + 2m²) = 4mn + \((-\frac{2}{5} - \frac{3}{5} + 2)m²\) = 4mn + \((\frac{-2-3+10}{5})m²\) = 4mn + (3/5)m²

3) 2cd² – 2dc² + 3cd² + 1,1d²c² + 2dc² = (2cd² + 3cd²) + (-2dc² + 2dc²) + 1,1d²c² = 5cd² + 0 + 1,1d²c² = 5cd² + 1,1d²c²

4) 3,7a²b – 3ab + 2ab² – 1,2a²b – 2ab² = (3,7a²b – 1,2a²b) + (-3ab) + (2ab² – 2ab²) = (3,7 – 1,2)a²b – 3ab + 0 = 2,5a²b

1) x³y² – 2xy² + 3x²y – 2x³y² – 3x²y – xy² = (x³y² – 2x³y²) + (-2xy² – xy²) + (3x²y – 3x²y) = -x³y² - 3xy² + 0 = -x³y² - 3xy²

2) 4mn³ – 5mn + 2m²n³ + mn³ – mn – 2m²n³ = (4mn³ + mn³) + (2m²n³ – 2m²n³) + (-5mn – mn) = 5mn³ + 0 - 6mn = 5mn³ - 6mn

3) ab + ab² + a²b – 2ab – ab² – 2a²b = (ab – 2ab) + (ab² – ab²) + (a²b – 2a²b) = -ab + 0 - a²b = -ab - a²b

4) c³d + cd + cd³ – 3c³d – cd – 3cd³ = (c³d – 3c³d) + (cd – cd) + (cd³ – 3cd³) = -2c³d + 0 - 2cd³ = -2c³d - 2cd³