Решение:
\[ \frac{5}{4} \cdot \frac{3}{5} = \frac{5 \cdot 3}{4 \cdot 5} = \frac{15}{20} = \frac{3}{4} \]
\[ -\frac{11}{2} + \frac{3}{4} \]
\[ -\frac{11 \cdot 2}{2 \cdot 2} + \frac{3}{4} = -\frac{22}{4} + \frac{3}{4} = \frac{-22 + 3}{4} = -\frac{19}{4} \]
\[ -\frac{19}{4} : \frac{9}{10} \]
\[ -\frac{19}{4} \cdot \frac{10}{9} = -\frac{19 \cdot 10}{4 \cdot 9} = -\frac{190}{36} \]
\[ -\frac{190}{36} = -\frac{95}{18} \]
\[ \frac{4}{3} + ( -\frac{95}{18} ) = \frac{4}{3} - \frac{95}{18} \]
\[ \frac{4 \cdot 6}{3 \cdot 6} - \frac{95}{18} = \frac{24}{18} - \frac{95}{18} = \frac{24 - 95}{18} = -\frac{71}{18} \]
Ответ: $$-\frac{71}{18}$$