Solution:
- The problem presents two fractions: \(\frac{x-7}{9}\) and \(\frac{4-x}{7}\).
- If the intention is to find when these two fractions are equal, we set up the equation:
- \(\frac{x-7}{9} = \frac{4-x}{7}\)
- Cross-multiplying gives:
- \(7(x-7) = 9(4-x)\)
- \(7x - 49 = 36 - 9x\)
- \(7x + 9x = 36 + 49\)
- \(16x = 85\)
- \(x = \frac{85}{16}\)
Answer: The expression \(\frac{x-7}{9}\) is equal to \(\frac{4-x}{7}\) when \(x = \frac{85}{16}\).