Вопрос:

766. 1) log2 (sqrt(2)); 2) log3 (1/sqrt(3)); 3) log0.5 (1/sqrt(32)); 4) log7 (sqrt(7)/49); 5) log128(64); 6) log27(243); 7) log64(256); 8) log81(27); 9) log(sqrt(1/(3*cbrt(3)))); 10) log1/2 (1/(4*sqrt(2)))

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Ответ:

766. Вычисление логарифмов

  1. 1) log2 √2
    Запишем √2 как 21/2. Тогда log2 21/2 = 1/2.
  2. 2) log3 (1/∛3)
    Запишем ∛3 как 31/3, тогда 1/∛3 = 3-1/3. log3 3-1/3 = -1/3.
  3. 3) log0,5 (1/√32)
    0,5 = 1/2 = 2-1. 32 = 25, √32 = 25/2, 1/√32 = 2-5/2.
    log2-1 2-5/2 = –5/2 / –1 = 5/2.
  4. 4) log7 (√7 / 49)
    √7 = 71/2. 49 = 72.
    √7 / 49 = 71/2 / 72 = 71/2 - 2 = 7-3/2.
    log7 7-3/2 = -3/2.
  5. 5) log128 64
    128 = 27, 64 = 26.
    log27 26 = 6/7.
  6. 6) log27 243
    27 = 33, 243 = 35.
    log33 35 = 5/3.
  7. 7) log64 256
    64 = 43, 256 = 44.
    log43 44 = 4/3.
  8. 8) log81 27
    81 = 34, 27 = 33.
    log34 33 = 3/4.
  9. 9) log (1/(3∛3))
    √ = 31/2. 3∛3 = 3 * 31/3 = 34/3.
    1/(3∛3) = 3-4/3.
    log31/2 3-4/3 = –4/3 / (1/2) = -8/3.
  10. 10) log1/2 (1/(4√2))
    1/2 = 2-1. 4√2 = 22 * 21/2 = 25/2.
    1/(4√2) = 2-5/2.
    log2-1 2-5/2 = –5/2 / –1 = 5/2.
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