75. Представьте в виде дроби:

Решение:

1. \( \frac{x}{2} + \frac{y}{3} = \frac{3x}{6} + \frac{2y}{6} = \frac{3x + 2y}{6} \)
2. \( \frac{a}{b} - \frac{b^2}{a} = \frac{a^2}{ab} - \frac{b^3}{ab} = \frac{a^2 - b^3}{ab} \)
3. \( \frac{c}{4} - \frac{d}{12} = \frac{3c}{12} - \frac{d}{12} = \frac{3c - d}{12} \)
4. \( \frac{3}{2x} - \frac{2}{3x} = \frac{9}{6x} - \frac{4}{6x} = \frac{9 - 4}{6x} = \frac{5}{6x} \)
5. \( \frac{5x}{8y} + \frac{x}{4y} = \frac{5x}{8y} + \frac{2x}{8y} = \frac{5x + 2x}{8y} = \frac{7x}{8y} \)
6. \( \frac{17y}{24c} - \frac{25y}{36c} = \frac{3 · 17y}{72c} - \frac{2 · 25y}{72c} = \frac{51y - 50y}{72c} = \frac{y}{72c} \)
7. \( \frac{1}{5a} - \frac{8}{25a} = \frac{5}{25a} - \frac{8}{25a} = \frac{5 - 8}{25a} = \frac{-3}{25a} \)
8. \( \frac{3b}{4c} + \frac{c}{2b} = \frac{3b · b}{4cb} + \frac{c · 2c}{4cb} = \frac{3b^2}{4bc} + \frac{2c^2}{4bc} = \frac{3b^2 + 2c^2}{4bc} \)